PSAT 8/9 Math — Semester A
Free Practice · 10 Questions · 20 min
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Question 1 of 10
TEKS ALGEasy

Solve for x:

5x + 1 = 51

A11
B9
C10
D15
Explanation
Subtract 1 from both sides: 5x = 50. Then divide both sides by 5: x = 10.
Question 2 of 10
TEKS ALGEasy

Solve for x:

6x + 12 = 42

A1
B5
C9
D4
Explanation
Subtract 12 from both sides: 6x = 30. Then divide both sides by 6: x = 5.
Question 3 of 10
TEKS ALGEasy

Solve for x:

8x + 15 = 39

A2
B4
C0
D3
Explanation
Subtract 15 from both sides: 8x = 24. Then divide both sides by 8: x = 3.
Question 4 of 10
TEKS PSDMedium

A product's price decreased from $150 to $90. What is the percent decrease?

A35%
B45%
C40%
D60%
Explanation
Percent change = (new − old) / old × 100% = (-60) / 150 × 100% = 40%.
Question 5 of 10
TEKS PSDMedium

A product's price decreased from $120 to $102. What is the percent decrease?

A20%
B10%
C15%
D85%
Explanation
Percent change = (new − old) / old × 100% = (-18) / 120 × 100% = 15%.
Question 6 of 10
TEKS ADVMedium

If f(x) = 6x² − 2x + 3, what is f(3)?

A57
B15
C51
D45
Explanation
f(3) = 6(3)² + (-2)(3) + 3 = 54 − 6 + 3 = 51.
Question 7 of 10
TEKS GEOMedium Diagram

In the right triangle shown, the hypotenuse has length 50 and one leg has length 14. What is the length of the other leg?

14?50
A46
B47
C44
D48
Explanation
By the Pythagorean theorem: b² = c² − a² = 50² − 14² = 2500 − 196 = 2304. So b = √2304 = 48.
Question 8 of 10
TEKS ADVMedium

If f(x) = 2x² − 3x + 8, what is f(4)?

A28
B30
C26
D4
Explanation
f(4) = 2(4)² + (-3)(4) + 8 = 32 − 12 + 8 = 28.
Question 9 of 10
TEKS ADVMedium

If f(x) = 4x² − 4x + 8, what is f(2)?

A8
B20
C16
D12
Explanation
f(2) = 4(2)² + (-4)(2) + 8 = 16 − 8 + 8 = 16.
Question 10 of 10
TEKS GEOMedium Diagram

In the right triangle shown, the hypotenuse has length 13 and one leg has length 5. What is the length of the other leg?

5?13
A12
B9
C11
D10
Explanation
By the Pythagorean theorem: b² = c² − a² = 13² − 5² = 169 − 25 = 144. So b = √144 = 12.

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